Expand each of the following,using suitable identities: $(-2x + 5y - 3z)^2$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) To expand $(-2x + 5y - 3z)^2$,we use the algebraic identity: $(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.
Here,$a = -2x$,$b = 5y$,and $c = -3z$.
Substituting these values into the identity:
$(-2x + 5y - 3z)^2 = (-2x)^2 + (5y)^2 + (-3z)^2 + 2(-2x)(5y) + 2(5y)(-3z) + 2(-3z)(-2x)$
Calculating each term:
$(-2x)^2 = 4x^2$
$(5y)^2 = 25y^2$
$(-3z)^2 = 9z^2$
$2(-2x)(5y) = -20xy$
$2(5y)(-3z) = -30yz$
$2(-3z)(-2x) = 12zx$
Combining these results,we get:
$4x^2 + 25y^2 + 9z^2 - 20xy - 30yz + 12zx$

Explore More

Similar Questions

Verify whether the following are zeroes of the polynomial indicated against them:
$p(x) = x^{2} - 1, x = 1, -1$

Factorise: $\frac{25}{4} x^{2}-\frac{y^{2}}{9}$

Factorise: $2x^2 + y^2 + 8z^2 - 2sqrt{2}xy + 4sqrt{2}yz - 8xz$

What are the possible expressions for the dimensions of the cuboids whose volumes are given below?
$\text{Volume} : 12ky^{2} + 8ky - 20k$

What are the possible expressions for the dimensions of the cuboids whose volumes are given below? $\boxed{\text{Volume} : 3x^2 - 12x}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo